Question 186680
Looking at 



*[Tex \LARGE \left(C' \cap A \right) \cup \left(C' \cap B' \right)]



notice how there is the common term C' and the alternation of set operators *[Tex \cap] and *[Tex \cup]. This means that the distributive property can be used here:



So


*[Tex \LARGE \left(C' \cap A \right) \cup \left(C' \cap B' \right)=C' \cap \left(A \cup  B' \right)]