Question 26051
Hey, 
I can help u with the first problem but I'm not sure about the second one.
OK...First, you need to either get the y or the x by itself, with this problem it's easier to get the y in equation 1. Since 3x is positive, subtract it from both sides of the eq. (from itself & 2). Like so:
3x+y=2(eq.1)
-3x -3x
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Switch it around:
y=-3x+2 Ah Ha! Now u know what y equals, so u can SUBSTITUTE it into eq.2!

2x-y=3(eq.2)
2x-(-3x+2)=3 Solve this:  
2x+3x-2=3 Add the two likes together(x's):
5x-2=3 Add 2 to both sides of the eq.:
  +2+2
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5x=5 Divide by 5:
*x=1* Ok...U have the x, now just find the y by useing SUBSTITUTION again!
Plug the x into eq.1:
3(1)+y=2 Now solve:
3+y=2 Subtract 3 from both sides:
-3 -3
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*y=-1* You've got y!
NOW, YOUR ANSWER IS(x,y):
*(1,-1)*

How to CHECK your answer,
Plug in the x & y into both equations:
3x+y=2
3(1)=-1=2
3=-1=2
2=2 CORRECT!

2x-y=3
2(1)-(-1)=2
2-(-1)=3
3=3 CORRECT!

I REALLY hope this helps!
~aShLeY~