Question 186636
Get the given line in the form y = mx + b
{{{2x+3y+6=0}}}
{{{3y = -2x - 6}}}
{{{y = (-2/3)x - 2}}}
{{{graph(400,400,-10,1,-10,10, -2x/3 -2)}}}

Now use point slope form
{{{y-y[1] = m*(x - x[1])}}}
{{{y-(-5) = m*(x - (-7))}}}
{{{y+5 = -2/3(x+7)}}}
{{{y+5 = -2x/3 - 14/3}}}
{{{y = -2x/3 - 14/3 - 5}}}
{{{y = -2x/3 -29/3}}}


{{{graph(400,400,-10,1,-10,10, -2x/3 -2, -2x/3 -29/3 )}}}