Question 186621
First, find the slope of the given line
{{{3x - 5y = 20}}}
{{{-5y = -3x + 20}}}
{{{y = (3/5)x - 4}}}
y = mx + b, so the slope of the given line is 3/5

The line perpendicular to this line has slope (-5/3) negative reciprocal

Now find the line that have slope -5/3 and passes thru (-1,0)
*[invoke find_line_by_slope_and_point -1, 0, -5/3]