Question 186594
y = x / (x-12) I'm a little confused about asymptotes and holes and want to make sure i'm doing it right. thank-you
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Your problem has an asymptote at x = 12 becuase x=12 would put 
a zero in the denominator and not in the numerator.
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Example of a "hole"
y = [(x+1)(x-12)/(x-12)  
This function has a "hold" at x=12 because x=12 would put
a zero in the denominator and ALSO in the numerator.
The graph of this function would look like the line y = x+1 but
it would have a "hold" at x=12

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Graph:
{{{graph(400,300,-10,20,-40,40,x/(x-12))}}}
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Cheers,
Stan H.