Question 186587
(w^2-1)/(w-1)*(w-1)/(w^2+2w+1)

Cancel the common factor w=1 to get:

= (w^2-1)/[w+1)^2]

= [(w-1)(w+1)]/[(w+1)^2]

Cancel the common factor w+1 to get:

= (w-1)/(w+1)

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Cheers,
Stan H.