Question 186583
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I can't believe that you mean:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  \frac{a}{a}+2>0]


Because that is a trivial statement being true for whatever value you choose for <i>a</i>.  So you must mean:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  \frac{a}{a+2}>0]


Multiply both sides by *[tex \Large a + 2]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  \frac{a}{a+2}(a + 2)>0(a+2)]



*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a > 0]


Interval notation:  [0,*[tex \Large \infty)]


Draw a little circle on the number line at zero.  Make a heavy line starting at the circle and going to the right-hand end of your representation of the number line putting an arrowhead on the heavy line on the right end.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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