Question 186566
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I've seen your problem--->the tutor answered it following the Ratio 3:4:5 , if "AC" being the shortest. Multiply each by <font color="red">4</font> in the ratio---->3*<font color="red">4</font color>=12="AC": 4*<font color="red">4</font>=16="BC" : 5*<font color="red">4</font>=20="AB"
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You got it?
Now, just a comment on this: If it's in the Ratio of 3:4:5, it forms a RIGHT TRIANGLE:
{{{drawing(400,400,-1,5,-1,4,triangle(0,0,0,3,4,0),green(line(0,.3,.3,.3)),green(line(.3,.3,.3,0)),red(locate(-.1,0,C)),red(locate(4.1,0,B)),red(locate(-.2,3.1,A)),green(locate(1.7,-.2,4=16yd)),green(locate(2.5,1.5,5=20yd)),green(locate(-.8,1.5,3=12yd)))}}}--->Proof: {{{5^2=3^2+4^2}}}-->{{{25=9+16}}}-->{{{25=25}}}
Finding for "AC":
{{{20^2=AC^2+16^2}}}
{{{AC^2=400-256=144}}}--->{{{AC=sqrt(144)=highlight(12yds)}}}
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Then, {{{P=AB+BC+AC=20+16+12=highlight(48 yds)}}}
Also, {{{A=(1/2)(BC)(AC)=(1/2)(16)(12)=highlight(96sqyds)}}}
The computations are right, as computed previously.
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Sorry, this is not to overemphasized the previous answer. We're just trying to make it clear for the student.
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Thank you,
Jojo</pre>