Question 26029
The denominators are: x; (x+5); x(x+5)
So, the LCD is x(x+5)
Multiply both sides by the LCD to get:
[(x+3)(x+5)] -[(x+4)(x)]= 15
[x^2+8x+15]-[x^2+4x]=15
4x+15=15
4x=0
 x=0
But x cannot be zero because it is the denominator
of the 1st fraction and is a factor of the denominator
of the right side.
The problem has no solution.
Cheers,
Stan H.