Question 186548
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1st condition:
{{{x+y=5(x-y)}}}
2nd condition:
{{{x=y+7}}}, ---->subst. in Condtn 1:
.
{{{x+y=5x-5y}}}
{{{y+7+y=5(y+7)-5y}}}
{{{2y+7=5y+35-5y}}}--->{{{2y=cross(5y)+35-cross(5y)-7}}}
{{{2y=28}}}--->{{{cross(2)y/cross(2)=cross(28)14/cross(2)}}}
{{{highlight(y=14)}}}
Then in Condtn 2:
{{{x=14+7}}}---->{{{highlight(x=21)}}}
Let's check via Condtn 1:
The sum of 2 numbers---->{{{14+21=35}}}
Equals 5 times their difference:
{{{35=5(21-14))}}}
{{{35=5(7)}}}
{{{35=35}}}
Thank you,
Jojo</pre>