Question 186434
Find the inverse of each function. Is the inverse a function? 
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f(x)=3x+2 
Interchange x and y to get:
x = 3y + 2
Solve for y
y = (1/3)x-(2/3)
Yes, it is a function
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Graph of the function and its inverse:
{{{graph(400,300,-10,10,-10,10,3x+2,(1/3)x-(2/3))}}}
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f(x)=x^2-5
Interchange:
x = y^2 -5
Solve for y:
y^2 = x+5
y = +sqrt(x+5) ; y = -sqrt(x+5)
No, it is not a function
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Graph of the function and its inverse:
{{{graph(400,300,-10,10,-10,10,x^2-5,(x+5)^(1/2), -(x+5)^(1/2))}}}
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Cheers,
Stan H.