Question 185966
find the 40th percentile of the normal curve with mean 80 and standard deviation 24.2. 
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The z-value corresponding to the 40%ile is -0.2533
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Find the x associated with that z-value:
z = (x-u)/s
-0.2533 = (x-80)/24.2
x-80 = 24.2*-0.2533
x-80 = -6.1299
x = 73.8701
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Cheers,
Stan H.