Question 186106
Perform the operations and simplify:
(a^3)^2/b^-1 / (a^3)-2/b^-1 
;
Assume the problem is
{{{(a^3)^2/b^-1}}}
---------
{{{(a^3)^-2/b^-1}}}
:
Multiply the numerator exponents
{{{(a^6)/b^-1}}}
---------
{{{(a^-6)/b^-1}}}
Reciprocals get rid of the neg exponents
{{{(a^6*b)/1}}}
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{{{(b)/a^6}}}
:
Invert the dividing fraction and multiply, b's cancel
{{{a^6*b}}} * {{{a^6/b}}} = {{{a^6*a^6}}} = {{{a^12}}}