Question 186091
{{{(a^(-2)b^5)^(-8)}}} 

The exponents here are -2 , 5 and -8. Of those three exponents, two are negative and one is positive. You need to know that {{{a^(-b) = 1/(a^b)}}}
Use this rule o f exponents to solve the given equation.

{{{(a^(-2)b^5)^(-8)}}} 
{{{a^16b^(-40)}}}
{{{a^16/b^40}}}