<PRE><B>Question 186008</B>
A newspaper advertises 5 different movies, 3 plays, and 2 baseball games for the weekend. If a couple selects 3 activities, find the probability that they attend 2 plays and 1 movie. 
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# of ways to pick 2 plays: 3C2 = 3 ways
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# of ways to pick 1 movie: 5C1 = 5 ways
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total number of ways to pick 2plays and 1 movie = 3*15 = 45 ways
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# of ways to select 3 activiies without restriction: 10C3 = (10*9*8)/(1*2*3)
= 120
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Therefore the prob (3 plays and 1 movie) = 45/120 = 3/8

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Cheers,
Stan H. </PRE>