Question 185898
First, graph the equation {{{y=x^2}}} (this curve will serve as the boundary)


Note: since there is an '=' sign in the inequality, this means that the boundary is a solid line



{{{ drawing(500, 500, -10, 10, -10, 10,
 graph( 500, 500, -10, 10, -10, 10,x^2)

)}}} Graph of {{{y=x^2}}}



Now pick a point that is NOT on the curve of {{{y=x^2}}}. Let's pick the point (0,1). This means that we have the values {{{x=0}}} and {{{y=1}}}. Now plug them into the inequality:


{{{y>=x^2}}} Go back to the inequality



{{{1>=0^2}}} Plug in {{{x=0}}} and {{{y=1}}}



{{{1>=0}}} Square 0 to get 0



Since this inequality is true, this means that we shade the ENTIRE region that this point lies in. So just shade the region above the graph to get the following:



<img src="http://i150.photobucket.com/albums/s91/jim_thompson5910/Algebra%20dot%20com/graph-1.png">



Graph of {{{y>=x^2}}} where the red line is the boundary equation {{{y=x^2}}} (solid line) with the shaded region in green.