Question 185852
c=20, a+b=28
a^2+b^2=c^2
x^2+(28-x)^2=20^2
x^2+x^2-56x+784=400
2x^2-56x+384=0
2(x^2-28x+192)=0
x^2-28x+192=0
x=12, x=16 these are the two sides.
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Ed
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*[invoke solve_quadratic_equation 1, -28, 192]