Question 185789
{{{x^2-8x+15=0}}}
{{{x^2-8x = -15}}} take half of 8 to get 4. then square that to get 16. Then add 16 to both sides
{{{x^2 -8x + 16 = -15 + 16}}}
{{{(x-4)^2 = 1}}}
Take square root of both side
(x-4) = 1  or (x-4) = -1
x = 5 or x = 3