Question 185683
Solve 6cos(theta) -3 square root(2) = 0, for 0 degrees is less than or equal to theta is less than or equal to 360 degrees.
--------------------------------
6cos(theta) -3 square root(2) = 0
Divide thru by 3 to get:
2cos(theta) - square root(2) = 0
cos(theta) = (sqrt(2))/2
------------------
Take the inverse cosine or arccos to get:
theta = 45 degrees or theta = 315 degrees.
============================================
Cheers,
Stan H>