Question 185557
x^2 + y^2=25
x + y^2=5
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x=5-y^2
(5-y^2)^2+y^2=25 substitute 5-y^2 for x.
y^4-10y^2+25+y^2=25
y^4-9y^2=0
y^2(y^2-9)=0
y^2(y+3)(y-3)=0
y=0, x=5; y=3, x=-4; y=-3 x=4
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Ed
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{{{graph(500,500,-10,10,-10,10,sqrt(25-x^2),sqrt(5-x),-sqrt(25-x^2),-sqrt(5-x))}}}