Question 185535
{{{(1/6)x^2-(1/2)x^3+x^2-(1/4)x^3+17}}} Start with the given expression.



{{{(-(1/2)x^3-(1/4)x^3)+((1/6)x^2+x^2)+17}}} Rearrange and group like terms (ie the terms that have the same exponent)



{{{(-(2/4)x^3-(1/4)x^3)+((1/6)x^2+x^2)+17}}} Multiply {{{-1/2}}} (the coefficient of the first term) by {{{2/2}}}



{{{(-(2/4)x^3-(1/4)x^3)+((1/6)x^2+(6/6)x^2)+17}}} Multiply {{{1}}} (the coefficient of the fourth term) by {{{6/6}}}



{{{-(3/4)x^3+(7/6)x^2+17}}} Combine like terms by combining the fractional coefficients.




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Answer:




So {{{(1/6)x^2-(1/2)x^3+x^2-(1/4)x^3+17}}} simplifies to {{{-(3/4)x^3+(7/6)x^2+17}}}



In other words, {{{(1/6)x^2-(1/2)x^3+x^2-(1/4)x^3+17=-(3/4)x^3+(7/6)x^2+17}}}