Question 185512
 Another story problem I can't seem to understand. 
Paul has $1.47 in change consisting of pennies, nickels and quarters. He has three more pennies than quarters and one more nickel than pennies. How many of each coin does he have?
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p = q+3 (3 more pennies than quarters)
n = p+1
p + 5n + 25q = 147 (the total)
-------------Substitute for n and q
p + 5(p+1) + 25(p-3) = 147
p + 5p+5 + 25p-75 = 147
31p + 70 = 147
31p = 217
p = 7
You can do the other 2.