Question 185484
 Find the exact values of the six trigonometric functions of theta if the terminal side of theta in standard position contains the point (-5,-4). 
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You have x = -5 and y = -4 ; solve for "r".
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r^2 = 5^2 + 4^2 = 41
r = sqrt(41)
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sin(theta) = y/r = -5/sqrt(41)
cos(theta) = x/r = -4/sqrt(41)
tan(theta) = y/x = 5/4
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the csc, sec, and cot are the inverse of the sin, cos and tan.
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Cheers,
Stan H.