Question 185343
{{{(x+1)^2=(x+1)(x+1)=(x)(x)+x(1)+1(x)+1(1)=x^2+x+x+1=x^2+2x+1}}}



So {{{(x+1)^2=x^2+2x+1}}}



Note: {{{x^2+2x+1}}} is a perfect square trinomial