Question 185214
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Let <i>A</i> be the number of Amelie's fish.  Let <i>B</i> be the number of If Benoit's fish.


If B gives up 2 fish he will have <i>B</i> - 2 fish.  And if A gets 2 fish, she will have <i>A</i> + 2 fish.  And we know that A now has 2 times as many fish as B, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  A + 2 = 2(B - 2)]


If A gives up 4 fish, she will have <i>A</i> - 4 fish.  If B gets 4 fish he will have <i>B</i> + 4 fish.  The problem tells us that these two quantities are equal, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  A - 4 = B + 4]


Since you have been given a word problem that requires solving simultaneous linear equations, you must already know how to find the solution set of a system.  Solve the above system for <i>A</i> and <i>B</i>.  I suggest you use the substitution method.


Later that day...


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  A + 8 = 3(B - 8)]


and


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  A - \frac{A}{5} = B + \frac{A}{5}]


This will be somewhat simpler if you first multiply the 2nd equation by 5 before you collect like terms and solve for A.  Again, use the substitution method.


And please stop asking God for help with your mathematics.  The only thing you will get from God is an opportunity to study, and you have lots of those already.  And while you are at it, stop screaming at us by using ALL CAPS.  It is the electronic equivalent of shouting and is both rude and annoying.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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