Question 185230
solve the equation. log(x+2)= -log(x-1) +1
Assuming all are "common logs", base 10
log(x+2) + log(x-1) = 1
log((x+2)*(x-1)) = log(10)
(x+2)*(x-1) = 10
x^2 + x - 2 = 10
x^2 + x - 12 = 0
*[invoke solve_quadratic_equation 1,1,-12]
Ignore the -4
x = 3