Question 185228
The quotient rule says this: {{{x^y/x^z = x^(y-z)}}}.

So in the equation {{{p^6*q^8/p^2q^4}}} we can use the same concept and do the following to it:

{{{p^6*q^8/p^2q^4 = p^(6-2)q^(8-4)}}}

Then simplify the exponents and we get:

{{{p^4*q^4}}}

Hope this helps.