Question 185198
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Let <i>h</i> be the height you are looking for.  Then let *[tex \Large h_1] be the height after the 1st bounce and *[tex \Large h_2] be the height after the 2nd bounce.  Then 70% of *[tex \Large h_2] equals 10.29 m, which is then equal to 70% of *[tex \Large h_1], which is then equal to 70% of *[tex \Large h], so:



*[tex \LARGE \ \ \ \ \ \ \ \ \ \  (0.70(0.70(0.70h))) = 10.29 \ \ \Rightarrow\ \ h = \frac{10.29}{(0.70)^3}]


You can do your own arithmetic.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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