Question 185172
First, the solutions to the general form of the quadratic equation:
{{{ax^2+bx+c = 0}}} are:
{{{x = (-b+sqrt(b^2-4ac))/2a}}} and {{{x = (-b-sqrt(b^2-4ac))/2a}}} so we need to find the product of these solutions.
{{{((-b+sqrt(b^2-4ac))/2a)*((-b-sqrt(b^2-4ac))/2a) = (b^2-(b^2-4ac))/4a^2}}} Simplifying this, we get:
{{{(b^2-b^2+4ac)/4a^2 = highlight(c/a)}}}