Question 185158
let x be one number, then (x+1) is the other number
{{{x^2 + (x+1)^2 = 25}}}
{{{x^2 + x^2 + 2x + 1 = 25}}}
{{{2x^2 + 2x -24 = 0}}}
{{{x^2 + x -12 = 0}}}
{{{(x+4)(x-3) = 0}}}
x = -4 and x = 3
so then numbers are 3,4 and -4,-3