Question 25804
Each two digit number has two numbers (duh!).

Let's allow the tens digit to be x and the units digit to be y.

Tens digit is 3 less than the units digit:  x = y-3

Original number is 6 more than 4 times the sum of the digits:  10x+y-6 = 4x + 4y

This gives us simulataneous equations!
First let's clear the mess:

1. x= y-3
2. 6x-3y=6

Substitute 1 into 2:

6(y-3) -3y =6
6y - 18 - 3y = 6
3y = 24
y = 8

Our units digit is 8

Substitute y= 8 into 1.

x = y - 3
x = 5

Our tens digit is 5

Therefore, our number is 58.

Let's test this.

Tens digit is 3 less than units digit: 58  -->  5 is 3 less than 8! 
Original number is 6 more than 4 times the sum of the digits --> sum of the digits = 13, 4 times the sum of the digits = 52, Add 6, 58!

We have proven that our number is 58!