Question 185124
6^(n-5) x 3^(5-n)

=

[2^(n-5) x 3^(n-5)] x 3^(5-n)

=

2^(n-5) x [3^(n-5) x 3^(5-n)]

=

2^(n-5) x [1] because 3^(n-5) x 3^(5-n) = 3^0 = 1

=

2^(n-5)