Question 185049
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Let <i>w</i> be the width, then <i>w</i> + 8 is the length.  So the area is:



*[tex \LARGE \ \ \ \ \ \ \ \ \ \  w(w+8)=200]


In standard form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  w^2 + 8w - 200 = 0]


Solve using the quadratic formula, discarding the negative root giving you the width.  Then add 8 to get the length.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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