Question 185067
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Let the measure of the smaller angle be <i>x</i>.  Then the measure of the larger angle must be 3<i>x</i> - 20.  The sum of the measures of these two angles must be 120, thus:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x + (3x - 20) = 120]


Solve for <i>x</i> to get the measure of the smaller angle, and subtract that value from 120 to get the measure of the larger.  Check your answer by multiplying the measure of the smaller angle by 3 and subtracting 20 to see if the result is what you got for the larger angle.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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