Question 185032
Find the vertex and axis of symmerty of y=2X^2+6X
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Put the equation in vertex form by completing the square:

2(x^2 + 3x + ? ) = y
2(x^2 + 3x + (3/2)^2) = y + 2(3/2)^2

2(x+(3/2))^2 = y + (9/2)

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Vertex: (-3/2,-9/2)
Axis of symmetry: x = -3/2
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{{{graph(400,300,-10,10,-10,10,2x^2+6x)}}}
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Cheers,
Stan H.