Question 184976
{{{2y/9-5/6=y/9-1/2}}} Start with the given equation



{{{cross(18)^2(2y/cross(9))-cross(18)^3(5/cross(6))=cross(18)^2(y/cross(9))-cross(18)^9(1/cross(2))}}} Multiply EVERY term by the LCD 18 to clear the fractions out.



{{{2(2y)-3(5)=2(y)-9(1)}}} Simplify



{{{4y-15=2y-9}}} Multiply



{{{4y=2y-9+15}}} Add 15 to both sides



{{{4y-2y=-9+15}}} Subtract 2y from both sides



{{{2y=6}}} Combine like terms.



{{{y=6/2}}} Divide both sides by 2 to isolate "y" 



{{{y=3}}} Reduce



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Answer:


So the solution is {{{y=3}}}