<PRE><B>Question 184884</B>
f(x)=(x+3)&lt;sup&gt;2&lt;/sup&gt;(x-5)&lt;sup&gt;6&lt;/sup&gt;

Step 1: set f(x) to zero.

:: f(x)=(x+3)&lt;sup&gt;2&lt;/sup&gt;(x-5)&lt;sup&gt;6&lt;/sup&gt;=0

Note: if ab=0, then a=0 or b=0

Step 2: Solve (x+3)&lt;sup&gt;2&lt;/sup&gt;=0

:: (x+3)&lt;sup&gt;2&lt;/sup&gt;=0
:: x+3=0
:: x=-3

Step 3: Solve (x-5)&lt;sup&gt;6&lt;/sup&gt;

:: (x-5)&lt;sup&gt;6&lt;/sup&gt;=0
:: x-5=0
:: x=5

The roots are -3 of multiplicity 2 and 5 of multiplicity 5.

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