Question 184869
Your equation is already in the "slope-intercept" form of y = mx+b
{{{y = (8/7)x-1}}} where the slope, {{{m = 8/7}}} and the y-intercept is {{{b = -1}}}
Now this is a linear equation, which means it will graph into a straight line, and you need only two points to define a straight line.
To get those two points, you first set x = 0 and solve the equation for y, then you set y = 0 and solve the equation for x, like this...
{{{y = (8/7)x-1}}} Set x = 0 and solve for y.
{{{y = (8/7)(0)-1}}}
{{{y = -1}}} So the first point is (0, -1)
{{{y = (8/7)x-1}}} Set y = 0 and solve for x.
{{{0 = (8/7)x-1}}} Add 1 to both sides.
{{{1 = (8/7)x}}} Now multiply both sides by the multiplicative inverse of {{{8/7}}} and this is {{{7/8}}}
{{{1(7/8) = x}}} The second point is (7/8, 0)
Now plot these two points on your coordinate graph paper and joint the point with a straight.
{{{graph(400,400,-5,5,-5,5,(8/7)x-1)}}}