Question 184902
Factor:
You really should use parentheses to clearly define the problem!
Is it (1) {{{x^3m+y^3m}}} or
(2) {{{x^(3m)+y^(3m)}}}???
If it's (1), then:
{{{x^3m+y^3m}}} First factor an m.
{{{m(x^3+y^3)}}} Now factor the sum of two cubes as:
{{{m(x+y)(x^2-xy+y^2)}}}
If (2), then:
{{{x^(3m)+y^(3m)}}} Factor the sum of two cubes:
{{{(x^m+y^m)(x^(2m)-x^m*y^m+y^(2m))}}}