Question 184857
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Let <i>x</i> be the amount of the cheap cheese.  Then 8<i>x</i> is the price of all the cheap cheese.


Since there are 56 pounds of cheese total, the amount of expensive cheese must be 56 - <i>x</i>.  The price of all the expensive cheese is then *[tex \Large 12(56 - x)].


The price of the entire 56 pounds of mixture is *[tex \Large 56 \times 10.50 = 588]


Since there is nothing else in the mixture, the price of all the cheap cheese plus the price of all the expensive cheese must equal the price of the mixture:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  8x + 12(56 - x) = 588]


Solve for  <i>x</i> to get the amount of $8 cheese, and then subtract that amount from 56 to get the amount of $12 cheese.


I'll have a glass of wine with that, thank you.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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