Question 184804
<h4>x-intercept</h4>

To find the x-intercept, plug in {{{y=0}}} and solve for x



{{{7x-3y=-21}}} Start with the given equation.



{{{7x-3(0)=-21}}} Plug in {{{y=0}}}.



{{{7x-0=-21}}} Multiply {{{-3}}} and 0 to get 0.



{{{7x=-21}}} Simplify.



{{{x=(-21)/(7)}}} Divide both sides by {{{7}}} to isolate {{{x}}}.



{{{x=-3}}} Reduce.



So the x-intercept is *[Tex \LARGE \left(-3,0\right)].



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<h4>y-intercept</h4>

To find the y-intercept, plug in {{{x=0}}} and solve for y



{{{7x-3y=-21}}} Start with the given equation.



{{{7(0)-3y=-21}}} Plug in {{{x=0}}}.



{{{0-3y=-21}}} Multiply {{{7}}} and 0 to get 0.



{{{-3y=-21}}} Simplify.



{{{y=(-21)/(-3)}}} Divide both sides by {{{-3}}} to isolate {{{y}}}.



{{{y=7}}} Reduce.



So the y-intercept is *[Tex \LARGE \left(0,7\right)].




Now plot the points *[Tex \LARGE \left(-3,0\right)] and *[Tex \LARGE \left(0,7\right)]



{{{ drawing(500, 500, -8, 5, -5, 8,
grid(1),
graph(500, 500, -8, 5, -5, 8,0),
circle(0,7,0.08),circle(0,7,0.10),circle(0,7,0.12),
circle(-3,0,0.08),circle(-3,0,0.10),circle(-3,0,0.12)
)}}} 





Draw a straight line through these points to graph {{{7x-3y=-21}}}


{{{ drawing(500, 500, -8, 5, -5, 8,
grid(1),
graph(500, 500, -8, 5, -5, 8,(-21-7x)/(-3)),
circle(0,7,0.08),circle(0,7,0.10),circle(0,7,0.12),
circle(-3,0,0.08),circle(-3,0,0.10),circle(-3,0,0.12)
)}}} Graph of {{{7x-3y=-21}}}