Question 184660
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \  a^{-n}=\frac{1}{a^n}]


so



*[tex \LARGE \ \ \ \ \ \ \ \ \ \ d^{-1} \cdot 1700 = \frac{1}{d^1} \cdot 1700 = \frac{1}{d} \cdot 1700 = \frac{1700}{d}]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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