Question 184636
bx + ay = 2ab
bx - ay = 4ab
----------------adding eliminates ay
2bx = 6ab
Divide both sides by 2b
x = 3a
;
Find y, substitute 3a for x in the 1st equation
b(3a) + ay = 2ab
3ab + ay = 2ab
ay = 2ab - 3ab
ay = -ab
divide both sides by a
y = -b
;
;
Check solution in the 2nd equation substitute for x and y:
bx - ay = 4ab
b(3a) - a(-b) = 4ab
3ab + ab = 4ab