Question 184633
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \  \log_4(\log_3(\log_2{N}))=1]


Remember that:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log_b{x} = y \ \ \Rightarrow\ \ b^y = x]


So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log_4{x} = 1 \ \ \Rightarrow\ \ x = 4^1 = 4]


So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log_3(\log_2{N})=4]


And:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log_3{x} = 4 \ \ \Rightarrow\ \ x = 3^4 = 81]


So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log_2{N}=81]


And finally:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log_2{N} = 81 \ \ \Rightarrow\ \ N = 2^{81}]


A <i><b>very</b></i> large number indeed.  2,417,851,639,229,258,349,412,352


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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