Question 184550
y=2(x+2)²+4
y=2(x^2+4x+4)+4
y=2x^2+8x+8+4
y=2x^2+8x+12
{{{ graph( 300, 200, -6, 5, -10, 10, 2x^2 +8x +12) }}} (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, 2x^2 +8x +12).
Using the x=-2 value we get:
y=2(-2+2)^2+4
y=2*0+4
y=4 ans.
(-2,4) is the vertex.
If x=-4 then:
y=2(-4+2)^2+4
y=2*-2^2+4
y=2*4+4
y=8+4
y=12
(-4,12) is another point on the parabola.