Question 184470
(2x + 3)^2 = 5 
4x^2+12x+9-5=0
4x^2+12x+4=0
*[invoke quadratic "x", 4, 12, 4 ]
x=-2.6, x= -0.38


2(x - 5)^2 = 3 
2(x^2-10x+25)=3
2x^2-20x+47=0
x=3.775
x=6.224