Question 184469
Give the equation of the axis of symmetry of y = -x^2 - 3x - 5. 
----------------
Complete the square on the "x" terms.
-x^2 - 3x = y+5
-(x^2 + 3x +?) = y+5-?
-(x^2 + 3x + (3/2)^2) = y+5 -(3/2)^2
-(x+(3/2))^2 = y + 20/4 -9/4
-(x+3/2)^2 = y + 11/4
--------------------------
Axis of symmetry: x = -3/2
--------------------------
{{{graph(400,300,-10,10,-20,10,-x^2-3x-5)}}}
===============================================
Cheers,
Stan H.