Question 184347
A =6V^(2/3) 
6V^(2/3)=12
v^(2/3)=2 divide each side by 6
v^2=2^3 cube each side
v=2^(3/2)ft^3 Take sqrt of each side.
=sqrt(8)
=sqrt(4*2)
=2sqrt(2)
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Let n=winston's time
willie's time=n+1
In 1 hr winston can do 1/n of the job.
In 1 hr willie can do 1/(n+1) of the job
Together they can do 1/2 the job in 1 hr
1/n + 1/(n+1) = 1/2
2(n+1)+2n=n(n+1) Multiply each side by the LCM 2n(n+1)
2n+2+2n=n^2+n
4n+2=n^2+n
n^2-3n-2=0 subtract the left side from the right.
n=3.56...hrs winston's time. (see below)
4.56...hrs willie's time.
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I don't think you copied the 3rd question corectly because as written it gives a minimum not a maximum.
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Ed
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*[invoke solve_quadratic_equation 1, -3, -2]