Question 184350
{{{q(x)= 5x^2+4}}} Start with the given function.



{{{q(2a)= 5(2a)^2+4}}} Plug in {{{x=2a}}}



{{{q(2a)= 5(4a^2)+4}}} Square {{{2a}}} to get {{{4a^2}}}



{{{q(2a)= 20a^2+4}}} Multiply



{{{5(q(2a))= 5(20a^2+4)}}} Multiply both sides by 5



{{{5(q(2a))= 5(20a^2)+5(4)}}} Distribute



{{{5(q(2a))= 100a^2+20}}} Multiply