Question 184303
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \ \ 2y - x = 18]


Remember that ordered pairs are of the form (<i>x</i>,<i>y</i>).  If the graph of an equation passes through a point, then the coordinates of that point (the <i>x</i> and <i>y</i> in the ordered pair) must make the equation a true statement.  So then what is the value of <i>x</i> when <i>y</i> = 0?


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \ \ 2(0) - x = 18\ \ \Rightarrow\ \ -x=18\ \ \Rightarrow\ \ x = -18]


The other 3 points were derived in the same way, just by substituting zero for the appropriate variable.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \ \ x + 0 = 6]


So <i>x</i> = 6 when <i>y</i> = 0 and the point (6,0) is on the line.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \ \ 0 + y = 6]


So <i>y</i> = 6 when <i>x</i> = 0 and the point (0,6) is on the line.


and for the other equation:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \ \ 2y + 0 = 18 \ \ \Rightarrow\ \ y = 9]


So <i>y</i> = 9 when <i>x</i> = 0 and the point (0,9) is on the line.


John
*[tex \Large e^{i\pi} + 1 = 0]
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